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4v^2-19v-30=0
a = 4; b = -19; c = -30;
Δ = b2-4ac
Δ = -192-4·4·(-30)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-29}{2*4}=\frac{-10}{8} =-1+1/4 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+29}{2*4}=\frac{48}{8} =6 $
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